Problem Statement
How much water must be added to 30 L of 20% alcohol solution to reduce it to 15% alcohol?
Explanation
Alcohol amount stays at six liters. Let final volume be V. Six equals zero point one five V, so V equals forty. Added water is forty minus thirty equals ten liters.
Code Solution
SolutionRead Only
0.20×30 = 0.15×V ⇒ V=40 ⇒ add=10
