How can you pass and access command-line arguments in a shell script?

Problem Statement

Explanation

Arguments are passed after the script name and accessed using positional parameters like $1, $2, and so on. $0 refers to the script name, and $# gives the total count of arguments.

Code Solution

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echo 'First argument:' $1
echo 'Total args:' $#

Practice Sets

This question appears in the following practice sets:

Advanced Shell Commands & Automation

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How can you pass and access command-line arguments in a shell script?

Problem Statement

Explanation

Code Solution

Practice Sets

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Master Interviews Anywhere, Anytime

How can you pass and access command-line arguments in a shell script?

Problem Statement

Explanation

Code Solution

Practice Sets

Related Questions

Which command lists all files including hidden ones in Linux?

Which command prints the current working directory path?

Which command moves you one directory up in Linux?

Which command combination creates and removes directories?

Which command moves files in Linux?

More from Linux & Shell Scripting

Master Interviews
Anywhere, Anytime