Problem Statement
Find the least number which when divided by 4, 5 and 6 leaves a remainder 3.
Explanation
If N leaves remainder 3 with all, then N−3 is divisible by LCM(4,5,6)=60.
So least N = 60 + 3 = 63.
Code Solution
SolutionRead Only
LCM(4,5,6)=60 ⇒ N=60k+3 → k=1 ⇒ 63
