Problem Statement
Calls arrive at a helpdesk at a mean rate of 2 per minute (Poisson). What is the probability of exactly 3 calls in a minute?
Explanation
P(X=3) = e^{−2} 2^3 / 3! = e^{−2}·8/6 ≈ 0.180.
Code Solution
SolutionRead Only
P(3) = e^{-2} * 8/6