A disease has prevalence 1%. A test has sensitivity 99% and specificity 95%. If a person tests positive, what is the approximate probability they actually have the disease?

Problem Statement

Explanation

Bayes: P(D|+) = 0.01×0.99 / [0.01×0.99 + 0.99×0.05] = 0.0099 / 0.0594 ≈ 0.167.

Code Solution

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0.0099/(0.0099+0.0495)≈0.167

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Probability & Statistics (Basics)

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A disease has prevalence 1%. A test has sensitivity 99% and specificity 95%. If a person tests positive, what is the approximate probability they actually have the disease?

Problem Statement

Explanation

Code Solution

Practice Sets

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A disease has prevalence 1%. A test has sensitivity 99% and specificity 95%. If a person tests positive, what is the approximate probability they actually have the disease?

Problem Statement

Explanation

Code Solution

Practice Sets

Related Questions

What is the sum of first 50 natural numbers?

Find the HCF of 12 and 18.

Find the LCM of 12 and 18.

Simplify: 25 + 15 × 3 - 10 ÷ 2

A number when divided by 5 leaves remainder 3. What will be the remainder when the square of this number is divided by 5?

More from Aptitude & Reasoning

Master Interviews
Anywhere, Anytime