Problem Statement
A container contains total 120 liters mixture of milk and water in which quantity of water is 20 liters. If 36 liters mixture is taken out and 6 liters milk added, then by what percent (approx.) is water less than milk in the final mixture?
Explanation
Milk:water = 100:20 = 5:1. Water left = 20 − 36×(1/6) = 14. Milk = 100 − 36×(5/6) + 6 = 76. Percent less = (76−14)/76 ×100 = 81.67% ≈ 82%.
Practice Sets
This question appears in the following practice sets: